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thaylaneps
@thaylaneps
October 2020
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03. (UEL-PR) No circuito representado no esquema a seguir, a
resistência de R2 é igual ao triplo da
resistência R1.
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Verified answer
U = R2 * i
6 = R2 * 0,30
R2 = 20 Ohms
R1= R2/3
R1 = 20/3 Ohms
Req = R1*R2/R1+R2
Req = (20*20/3) / (20+20/3)
Req = 400/3 / 80 / 3
Req = 400/3 * 3/80
Req = 400/80
Req = 5 Ohms
Achando o valor de R
U = Req * i
6 = 5 * i
6/5 = i
i = 1,2 A
U = R * i
6 = R * 1,2
6/1.2 = R
R = 5 Ohms
Alternativa C
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Verified answer
U = R2 * i6 = R2 * 0,30
R2 = 20 Ohms
R1= R2/3
R1 = 20/3 Ohms
Req = R1*R2/R1+R2
Req = (20*20/3) / (20+20/3)
Req = 400/3 / 80 / 3
Req = 400/3 * 3/80
Req = 400/80
Req = 5 Ohms
Achando o valor de R
U = Req * i
6 = 5 * i
6/5 = i
i = 1,2 A
U = R * i
6 = R * 1,2
6/1.2 = R
R = 5 Ohms
Alternativa C
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