Bonjour,
voir cours : (10ᵃ)ᵇ = 10ᵃˣᵇ
10ᵃ/10ᵇ = 10ᵃ⁻ᵇ
donc : (10³)⁴/10⁵ = 10³ˣ⁴⁻⁵ = 10⁷
(10²)⁴/10⁹ = 10²ˣ⁴⁻⁹ = 10⁻¹
Bonsoir.
(n^a)^b = n^(a x b)
n^a/n^b = n^(a - b)
1) (10^3)^4 = 10^12
10^12/10^5 = 10^7
2) (10^2)^4 = 10^8
10^8/10^9 = 10^(-1)
Bonne soirée !
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Verified answer
Bonjour,
voir cours : (10ᵃ)ᵇ = 10ᵃˣᵇ
10ᵃ/10ᵇ = 10ᵃ⁻ᵇ
donc : (10³)⁴/10⁵ = 10³ˣ⁴⁻⁵ = 10⁷
(10²)⁴/10⁹ = 10²ˣ⁴⁻⁹ = 10⁻¹
Verified answer
Bonsoir.
(n^a)^b = n^(a x b)
n^a/n^b = n^(a - b)
1) (10^3)^4 = 10^12
10^12/10^5 = 10^7
2) (10^2)^4 = 10^8
10^8/10^9 = 10^(-1)
Bonne soirée !