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evadtp
@evadtp
June 2021
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1. Etudier le signe du produit (3x-1)(2x+5).
2. En déduire les solutions de l'inéquation :
a) (3x-1)(2x+5)<0
b) (3x-1)(2x+5)≥0
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Kitephx
1. (3x-1)(2x+5)
=3x*2x+3x*5-1*2x-1*5
=6x²+15x-2x-5
= 6x²+13x-5
delta = b² -4ac
= 13²-4*6*-5
=289
delta > 0 donc il y a deux solutions
x1 =
(-b+Delta)/(2*a) = -5/2 = -2.5
x2 = (-b-Delta)/(2*a)
= 1/3
Si tu as besoin de la question 2 je te la fais après :)
4 votes
Thanks 4
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=3x*2x+3x*5-1*2x-1*5
=6x²+15x-2x-5
= 6x²+13x-5
delta = b² -4ac
= 13²-4*6*-5
=289
delta > 0 donc il y a deux solutions
x1 = (-b+Delta)/(2*a) = -5/2 = -2.5
x2 = (-b-Delta)/(2*a) = 1/3
Si tu as besoin de la question 2 je te la fais après :)