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Marianne78
@Marianne78
April 2019
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1 exercice de physique! J'y arrive pas si quelqu'un peut m'aider pour le 1 et 2 !
merci :)
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elo62
1) Q noyau= ZxQ proton
Z = Q noyau/Q proton
Z= (2,08x10^-18)/(1,6x10^-19)
Z= 13
Il y a 13 protons dans le noyau.
2) A = Z+N
A= 13+14
A= 27
Il y a 27 nucléons dans le noyau.
1 votes
Thanks 1
elo62
:)
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Z = Q noyau/Q proton
Z= (2,08x10^-18)/(1,6x10^-19)
Z= 13
Il y a 13 protons dans le noyau.
2) A = Z+N
A= 13+14
A= 27
Il y a 27 nucléons dans le noyau.