1) (PM ES – Funcab). Dada a função quadrática f(x) = -2.x² + 4.x – 9, as
coordenadas do vértice do gráfico da parábola definida por f(x), é:
A) V = (-7; 1)
B) V = (1; -7)
C) V = (0; 1)
D) V = (-7; 0)
E) V = (0; 0)

2) Calcule as raízes, o vértice e trace o gráfico da função f(x) = x² + 5x + 4.
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