1) Resolver as seguintes equações:
a) 2x - 10 = 30
b)x + 20 = 49
c) 5p -3 = 12
d) 4d + 4 = 2d + 12
e) 3m + 20 = 30 - m
f) 3 k -2k = 200
g) 3h - 40 = 12h - 20
h) 4y -3y + 20 = 50
i) 20 + 2 x + x = 30 + 20
a) 2x - 10 = 30
b)x + 20 = 49
c) 5p -3 = 12
d) 4d + 4 = 2d + 12
e) 3m + 20 = 30 - m
f) 3 k -2k = 200
g) 3h - 40 = 12h - 20
h) 4y -3y + 20 = 50
i) 20 + 2 x + x = 30 + 20
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Resposta:
(A) 2x-10=30
2x=30+10
2x=40
x=40÷2
x=20
(B) x+20=49
x=49-20
x=29
(C)5p-3=12
5p=12+3
5p=15
p=15÷5
p=3
(D)4d+4=2d+12
4d-2d=12-4
2d=8
d=8÷2
d=4