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Annabanana95
@Annabanana95
April 2019
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J'ai un trou de mémoire concernant les dérivations de fonction.
pouvez-vous m'aider à dériver celle-ci ? merci d'avance
f(x)=(x²+3)/(1-x)
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f(x)=(x²+3)/(1-x)
(u/v)'=(u'v-uv')/v²
f'(x)=((2x)(1-x)-(-1)(x²+3))/(1-x)²
=(-2x²+2x+x²+3)/(1-x)²
=(-x²+2x+3)/(1-x)²
=
((x+1)(3-x))/(1-x)²
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(u/v)'=(u'v-uv')/v²
f'(x)=((2x)(1-x)-(-1)(x²+3))/(1-x)²
=(-2x²+2x+x²+3)/(1-x)²
=(-x²+2x+3)/(1-x)²
=((x+1)(3-x))/(1-x)²