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clem30
@clem30
June 2021
1
54
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Pouvez vous maidez c'est urgent ! En utilisant les criteres de divisibilite rendre chacune de ces fraction ireductible :
126/81
39/21
240/105
merci de me donner les details si possible merci beaucoup !
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flo11
42/27 13/7 48/21 voila
0 votes
Thanks 1
clem30
Merci mais pouvez mexpliquer comment avez vous trouvez sa?
flo11
j ai diviser par 3 le 1er et le 2 eme et par 5 le 3 eme
clem30
Merci
flo11
de rien
flo11
a toi 1789/9875*9875*1789
flo11
1789/9875*9875/1789
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