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enttenten
@enttenten
January 2021
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19 POINTS URGENT
Bonjour qqun peut m'aider svp(avec explication):
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anylor
Bonjour
3)
c)
f(x) =(2-x)(x-1) = -x²+3x-2
racine de f(x)
u= 2
v=1
u+v /2 =3/2
f(3/2) = -(3/2)²+(3/2)×3 -2
= 1/4
l'algorithme affiche en sortie
3/2
1/4
( qui sont les coordonnées du sommet de f(x))
d)
x²-8x = x(x-8)
u=0
v=8
(u+v)/2 =8/2=4
f(4) = -16
l'algorithme affiche en sortie
4
-16
4)
cet algorithme calcule les coordonnées du sommet de la parabole
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Quelle est la figure destyle svp J'ai franchi le mur des ans.
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3)
c)
f(x) =(2-x)(x-1) = -x²+3x-2
racine de f(x)
u= 2
v=1
u+v /2 =3/2
f(3/2) = -(3/2)²+(3/2)×3 -2
= 1/4
l'algorithme affiche en sortie
3/2
1/4
( qui sont les coordonnées du sommet de f(x))
d)
x²-8x = x(x-8)
u=0
v=8
(u+v)/2 =8/2=4
f(4) = -16
l'algorithme affiche en sortie
4
-16
4)
cet algorithme calcule les coordonnées du sommet de la parabole