Articles
Register
Sign In
Search
andre99
@andre99
June 2021
1
62
Report
(1+1/2) (1+1/3)(1+1/4) x ...x (1+ 1/1999)
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
editions
Bonjour
1+1/2=3/2
1+1/3=4/3
.
.
1+1/1999=2000/1999
donc
(1+1/2) (1+1/3)(1+1/4) x ...x (1+ 1/1999)
=(3/2)*(4/3)*....*1998*1999*1999/2000
=(3*4*.........*1999)/(2*3*4*......*1999*2000)
en simplifiant ça donne 2000/2=1000
1 votes
Thanks 1
andre99
dernière parenthèse est pas resté deux multiplié par 2000
More Questions From This User
See All
andre99
June 2021 | 0 Respostas
Responda
andre99
June 2021 | 0 Respostas
Responda
andre99
June 2021 | 0 Respostas
Responda
×
Report "(1+1/2) (1+1/3)(1+1/4) x ...x (1+ 1/1999).... Pergunta de ideia de andre99"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
1+1/2=3/2
1+1/3=4/3
.
.
1+1/1999=2000/1999
donc
(1+1/2) (1+1/3)(1+1/4) x ...x (1+ 1/1999)=(3/2)*(4/3)*....*1998*1999*1999/2000
=(3*4*.........*1999)/(2*3*4*......*1999*2000)
en simplifiant ça donne 2000/2=1000