racionalizando 1-√3 / 2-√3 teremos ?.... Pergunta de ideia deyasminfolchini

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racionalizando 1-√3 / 2-√3 teremos ?

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$\dfrac{1- \sqrt{3} }{2- \sqrt{3} } = \dfrac{(1- \sqrt{3}).(2+\sqrt{3}) }{(2- \sqrt{3}).(2+\sqrt{3}) } = \dfrac{2+\sqrt{3}-2\sqrt{3}-3 }{4-3} = \dfrac{-\sqrt{3}-1 }{1}$ $=-\sqrt{3}-1$

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