Resposta:
[tex]\textsf{Leia abaixo}[/tex]
Explicação passo a passo:
[tex]\mathsf{\left(x + \dfrac{3}{2}\right)^2}[/tex]
[tex]\mathsf{\left(\dfrac{2x + 3}{2}\right)^2}[/tex]
[tex]\boxed{\boxed{\mathsf{\left(x + \dfrac{3}{2}\right)^2 = \dfrac{4x^2 + 12x + 9}{4}}}}[/tex]
[tex]\Large\boxed{\begin{array}{l}\underline{\rm Quadrado\,da\,soma\,de\,2\,termos}\\\sf \bigg(x+\dfrac{3}{2}\bigg)^2=x^2+\backslash\!\!\!2\cdot x\cdot\dfrac{3}{\backslash\!\!\!2}+\bigg(\dfrac{3}{2}\bigg)^2\\\\\sf\bigg(x+\dfrac{3}{2}\bigg)^2=x^2+3x+\dfrac{9}{4}\end{array}}[/tex]
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Resposta:
[tex]\textsf{Leia abaixo}[/tex]
Explicação passo a passo:
[tex]\mathsf{\left(x + \dfrac{3}{2}\right)^2}[/tex]
[tex]\mathsf{\left(\dfrac{2x + 3}{2}\right)^2}[/tex]
[tex]\boxed{\boxed{\mathsf{\left(x + \dfrac{3}{2}\right)^2 = \dfrac{4x^2 + 12x + 9}{4}}}}[/tex]
[tex]\Large\boxed{\begin{array}{l}\underline{\rm Quadrado\,da\,soma\,de\,2\,termos}\\\sf \bigg(x+\dfrac{3}{2}\bigg)^2=x^2+\backslash\!\!\!2\cdot x\cdot\dfrac{3}{\backslash\!\!\!2}+\bigg(\dfrac{3}{2}\bigg)^2\\\\\sf\bigg(x+\dfrac{3}{2}\bigg)^2=x^2+3x+\dfrac{9}{4}\end{array}}[/tex]