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Clocloml99
@Clocloml99
April 2019
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√2 cos x +1>0
Résoudre a laide du cercle trigonométrique
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√2.cos(x)+1>0
donc cos(x)>-1/√2
donc cos(x)>cos(3π/4)
donc
x∈[-3π/4;3π/4]
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Verified answer
√2.cos(x)+1>0donc cos(x)>-1/√2
donc cos(x)>cos(3π/4)
donc x∈[-3π/4;3π/4]