Resposta:

[tex]Se~x=\frac{2}{3} ~e~y=\frac{1}{2} ~entao~x+y~e~igual~a:\\ \\ \frac{2}{3} +\frac{1}{2}=\\ \\ mmc=6\\ \\ \frac{4+3}{6} =\frac{7}{6}[/tex]