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Lisienia22
@Lisienia22
October 2020
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2 – Estabelecer a equação da parábola, sabendo que: vértice: V(-4,6) e foco: F(-4,2).
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mauricovisk
Y^2 = - 2.p.x
(y-6)^2 = - 2.8.[x- ( -4)]
y^2 - 2.y.6 + 6^2 = - 16.(x+4)
y^2 -12y + 36 = - 16x - 64
y^2 -12y + 36 + 16x + 64 = 0
y^2 -12y + 16x +100 =0
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Lista de comentários
(y-6)^2 = - 2.8.[x- ( -4)]
y^2 - 2.y.6 + 6^2 = - 16.(x+4)
y^2 -12y + 36 = - 16x - 64
y^2 -12y + 36 + 16x + 64 = 0
y^2 -12y + 16x +100 =0