2) Factoriser les expressions suivantes : F(x) = (2x - 3)(x-2) - (2x - 3)(x+4) H(a) = (3x² + 2)(x-6) - (x + 7) (3x² + 2x) G(x)= (-2x + • 1(x) = (x - 2)
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F(x) = (2x - 3)(x-2) - (2x - 3)(x+4)
= (2x-3) [(x-2) - (x+4)]
= (2x-3) (x-2-x-4)
= -6 (2x-3)
H(a) = (3x² + 2)(x-6) - (x + 7) (3x² + 2x)
= (3x²+2) [(x-6) - (x+7)]
= (3x²+2) (x-6-x-7)
= -13 (3x²+2)
errur dans G(x)