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Nounoune2404
@Nounoune2404
April 2019
1
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On donne l'expression suivante
M=(2x-3)²-(x+5)(2x-3)
1) développer et réduire M
2)factoriser M
3)calculer M lorsque x=3/2 puis x=0
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Bonjour
1)
M = (2x - 3)² - (x + 5)(2x - 3)
= (4x² - 12x + 9) - (2x² - 3x + 10x - 15)
= 4x² - 12x + 9 - 2x² + 3x - 10x + 15
= 2x² - 19x + 24
2) M = (2x - 3)(2x - 3) - (x + 5)(2x - 3 )
= (2x - 3) [(2x - 3) - (x + 5)]
= (2x - 3) (2x - 3 - x - 5)
= (2x - 3) (x - 8)
3) x = 3/2
M = (2x - 3) (x - 8)
= (2 * (3/2) - 3)(3/2 - 8)
= (3 - 3)(3/2 - 8)
= 0 * (3/2 - 8)
= 0
x = 0
M = 2x² - 19x + 24
= 2 * 0 - 19* 0 + 24
= 0 - 0 + 24
= 24
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Lista de comentários
1) M = (2x - 3)² - (x + 5)(2x - 3)
= (4x² - 12x + 9) - (2x² - 3x + 10x - 15)
= 4x² - 12x + 9 - 2x² + 3x - 10x + 15
= 2x² - 19x + 24
2) M = (2x - 3)(2x - 3) - (x + 5)(2x - 3 )
= (2x - 3) [(2x - 3) - (x + 5)]
= (2x - 3) (2x - 3 - x - 5)
= (2x - 3) (x - 8)
3) x = 3/2
M = (2x - 3) (x - 8)
= (2 * (3/2) - 3)(3/2 - 8)
= (3 - 3)(3/2 - 8)
= 0 * (3/2 - 8)
= 0
x = 0
M = 2x² - 19x + 24
= 2 * 0 - 19* 0 + 24
= 0 - 0 + 24
= 24