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Deniz2318
@Deniz2318
April 2019
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Le 1,2 et 4 svp rédiger vos réponse en justifiant svp car la dernière fois j'ai eu 6/20 .. Alors que j'ai eu que des 14 d'habitude
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Mbelgacem
Tu es dans une configuration thalès
BD/BE = BC/BA = CD/AE
BD/BE = 3/(CA-3) = CD/AE
BD/BE = 3/5 = 4/AE
Tu utilises pythagore pour calculer bd
bd² = bc² + cd²
= 9 + 16 = 25
bd = 5
5/BE = 3/5 = 4/AE
3 be = 5*5
be = 25/3 = 8.3333
3 ae = 4 * 5
ae = 20/3 = 6.6666
normalement c'est bon
1 votes
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Lista de comentários
BD/BE = BC/BA = CD/AE
BD/BE = 3/(CA-3) = CD/AE
BD/BE = 3/5 = 4/AE
Tu utilises pythagore pour calculer bd
bd² = bc² + cd²
= 9 + 16 = 25
bd = 5
5/BE = 3/5 = 4/AE
3 be = 5*5
be = 25/3 = 8.3333
3 ae = 4 * 5
ae = 20/3 = 6.6666
normalement c'est bon