Bonjour. méthode de la distributivité (x²+2x-1).(x-3)=
(x4+3x²+7).(3x+2) =
(2x3-3x²+5).(4x²-1)=
(x²-5x+1).(x+3)=
(x2-3x-2).(x+1)=
(3x3-5x²+7x-4).(2x²-x+3)=
(x3-x2+x-1).(x+1)=
(x3-5x2+x).(x2+x+1)=
(x3-2x/5+1/3).5x/3-1/2)=
(x4+3x²+7).(3x+2) =
(2x3-3x²+5).(4x²-1)=
(x²-5x+1).(x+3)=
(x2-3x-2).(x+1)=
(3x3-5x²+7x-4).(2x²-x+3)=
(x3-x2+x-1).(x+1)=
(x3-5x2+x).(x2+x+1)=
(x3-2x/5+1/3).5x/3-1/2)=
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