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Elodie1234
@Elodie1234
April 2019
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(2x-5)(x+3)=2x²-(3x+1)+(x-6)
effectuer le calcul.
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Thomas1106
(2x-5)(x+3)=2x²-(3x+1)+(x-6)
2x*x + 2x*3 -5*x -5*3 =
2x²-3x-1+x-6
2x
²+6x-5x-15 = 2x² - 3x - 1 + x - 6
2x² + x - 15 = 2x² - 2x - 7
2x²
- 2x²
+ x
+ 2x
- 15
+ 15
= 2x²
- 2x²
- 2x
+ 2x
- 7
+ 15
3x = 8
x = 8/3
1 votes
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Lista de comentários
2x*x + 2x*3 -5*x -5*3 = 2x²-3x-1+x-6
2x²+6x-5x-15 = 2x² - 3x - 1 + x - 6
2x² + x - 15 = 2x² - 2x - 7
2x² - 2x² + x + 2x - 15 + 15 = 2x² - 2x² - 2x + 2x - 7 + 15
3x = 8
x = 8/3