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Oceanelefevres
@Oceanelefevres
April 2019
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Calculez la dérivée de f(x) : e^x / x , g(x) : (3 e^x-1)/ 2x et w(x) : xe^x
merci d'avance !
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slyz007
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F'(x)=(xe^x-e^x)/x²=(x-1)e^x/x
g'(x)=(2x*3e^x-2(3e^x-1))/4x²=(6xe^x-6e^x+2)/4x²=(3xe^x-3e^x+1)/2x²
w'(x)=e^x+xe^x=(x+1)e^x
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Verified answer
F'(x)=(xe^x-e^x)/x²=(x-1)e^x/xg'(x)=(2x*3e^x-2(3e^x-1))/4x²=(6xe^x-6e^x+2)/4x²=(3xe^x-3e^x+1)/2x²
w'(x)=e^x+xe^x=(x+1)e^x