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Ju0462
@Ju0462
May 2019
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Bonjour j’aurais besoin d’aide pour résoudre algébriquement les inéquations: a) 3x+2/x-5>=0. B) 4-7x/2x+1>=0. S’il vous plaît merci
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MonsieurFirdown
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Bonjour
♧a.
● On a :
≥0
--> Valeur interdite :
x - 5 ≠ 0
x ≠ 5
---> Et :
3x + 2 ≥0
3x ≥ - 2
x ≥
● D'où :
|---------x------|--(-∞)-------(-2/3)--------(5)------(+∞)--|
|------(3x+2)--|-------- (-) ----0---- (+) ------ (+) --------|
|-------(x-5)---|-------- (-)----------- (-) ---0-- (+) --------|
|(3x+2)/(x-5)|---------(+)-----0-----(-)----||---(+)---------|
S= ] -∞ ;
[ U ] 5 ; +∞ [
---> À toi de faire le deuxième....
Voilà ^^
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Lista de comentários
Verified answer
Bonjour♧a.
● On a :
≥0
--> Valeur interdite :
x - 5 ≠ 0
x ≠ 5
---> Et :
3x + 2 ≥0
3x ≥ - 2
x ≥
● D'où :
|---------x------|--(-∞)-------(-2/3)--------(5)------(+∞)--|
|------(3x+2)--|-------- (-) ----0---- (+) ------ (+) --------|
|-------(x-5)---|-------- (-)----------- (-) ---0-- (+) --------|
|(3x+2)/(x-5)|---------(+)-----0-----(-)----||---(+)---------|
S= ] -∞ ; [ U ] 5 ; +∞ [
---> À toi de faire le deuxième....
Voilà ^^