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Victor972
@Victor972
April 2019
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salut
2) a. On note p la fonction qui au nombre x choisi associe le resultat obtenu . Determiner l'expression de p(x).
b. Calculer (-1) , p(3) et p(2/3) .
c. Verifier 0,2 est l'antécédent de 10,2
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Verified answer
Bonjour,
je reprends la 2)
il faut faire le programme avec x :
x
x²
5x²
5x²+10
p(x) = 5x²+10
calculer p(1) :
on remplace x par 1
5(1)²+10 =
5+10 =15
p(2/3) :
5(2/3)²+10 =
5*4/9+10=
20/9+90/9 =
110/9
c) 5(0,2)²+10 =
0,2+10 = 10,2
3 votes
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Verified answer
Bonjour,je reprends la 2)
il faut faire le programme avec x :
x
x²
5x²
5x²+10
p(x) = 5x²+10
calculer p(1) :
on remplace x par 1
5(1)²+10 =
5+10 =15
p(2/3) :
5(2/3)²+10 =
5*4/9+10=
20/9+90/9 =
110/9
c) 5(0,2)²+10 =
0,2+10 = 10,2