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NoNameIsUseful
@NoNameIsUseful
April 2019
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Salut je dois calculer f(|/3), f(0) et f(4) et je dois choisir parmis ces 3 formules celle qui convient le mieux a chaque fois :
f1) f(x)= x²-8x+15 f2) f(x)= (x-4)²-1 f3) f(x)=(x-4) (x-4) -1
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nathalienouts
f1) f(x)= x²-8x+15
f2) f(x)= (x-4)²-1
f3) f(x)=(x-4) (x-4) -1
f1 : f(
√3) = √3²-8√3+15 = 3-8√3+15 = 18-8√3
f2 : f(0) = (0-4)²-1 = 16-1= 15
f3 : f(4) = (4-4)(4-4)-1 = 0x0-1 = -1
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NoNameIsUseful
April 2019 | 0 Respostas
Dm de maths je dois factoriser cette espression : b*c^3+2b^2+c^3+b^3*c autrement dit cela si vous ny ecrivez pas comme moi b*c*c*c+2b*b*c*c+b*b*b*c
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f2) f(x)= (x-4)²-1
f3) f(x)=(x-4) (x-4) -1
f1 : f(√3) = √3²-8√3+15 = 3-8√3+15 = 18-8√3
f2 : f(0) = (0-4)²-1 = 16-1= 15
f3 : f(4) = (4-4)(4-4)-1 = 0x0-1 = -1