Resposta:
-3ײ+18×-15=0. (÷ -3).
x² - 6x + 5 = 0.
(x-1). (x-5) = 0
x'=1 , x"=5.
Explicação passo a passo:
[tex] -3x^2+18x-15=0 [/tex]
[tex] a=-3\quad b=18\quad c=-15[/tex]
[tex] \Delta=b^2-4\cdot a\cdot c[/tex]
[tex] \Delta=18^2-4\cdot(-3)\cdot(-15) [/tex]
[tex] \Delta=324-180 [/tex]
[tex] \Delta=144 [/tex]
[tex] x=\dfrac{-b\pm\sqrt\Delta}{2\cdot a}[/tex]
[tex] x=\dfrac{-18\pm\sqrt{144}}{2\cdot(-3)} [/tex]
[tex] x=\dfrac{-18\pm12}{ -6}\begin{cases}x'=\dfrac{-18+12}{-6}=\dfrac{-6}{-6}=1\\\\x''=\dfrac{-18-12}{-6}=\dfrac{-30}{-6}=5\end{cases} [/tex]
[tex]\red{\boldsymbol{ S=\{1~;~5\}}}[/tex]
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Resposta:
-3ײ+18×-15=0. (÷ -3).
x² - 6x + 5 = 0.
(x-1). (x-5) = 0
x'=1 , x"=5.
Explicação passo a passo:
Verified answer
[tex] -3x^2+18x-15=0 [/tex]
[tex] a=-3\quad b=18\quad c=-15[/tex]
[tex] \Delta=b^2-4\cdot a\cdot c[/tex]
[tex] \Delta=18^2-4\cdot(-3)\cdot(-15) [/tex]
[tex] \Delta=324-180 [/tex]
[tex] \Delta=144 [/tex]
[tex] x=\dfrac{-b\pm\sqrt\Delta}{2\cdot a}[/tex]
[tex] x=\dfrac{-18\pm\sqrt{144}}{2\cdot(-3)} [/tex]
[tex] x=\dfrac{-18\pm12}{ -6}\begin{cases}x'=\dfrac{-18+12}{-6}=\dfrac{-6}{-6}=1\\\\x''=\dfrac{-18-12}{-6}=\dfrac{-30}{-6}=5\end{cases} [/tex]
[tex]\red{\boldsymbol{ S=\{1~;~5\}}}[/tex]