X designe un nombre relatif
A= x-5- 5/4x + 4/3
B= 3/4 (2-3x)
Reduire A et developper B
A= x-5- 5/4x + 4/3
B= 3/4 (2-3x)
Reduire A et developper B
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A= x-5- 5/4x + 4/3
A = x - 5/4 x - 5 + 4/3
A = -1/4 x - 15/3 + 4/3
A = -x/4 - 11/3
Developper B
B= 3/4 (2-3x)
B= 3*2/4 - 3/4*3x
B = 6/4 - 9/4 x
B = 3/2 - 9/4 x