Resposta:
A) f (-1) =
f(x) = 3 . (-1) + 5
f(x) = - 3 + 5
f(x) = 2
B) f (-3) =
f(x) = 3 . (-3) + 5
f(x) = - 9 + 5
f(x) = - 4
C) f ( 1/3 ) =
f(x) = 3 . [tex]\frac{1}{3}[/tex] + 5
f(x) = [tex]\frac{3}{1}[/tex] . [tex]\frac{1}{3}[/tex] + [tex]\frac{5}{1}[/tex]
f(x) = [tex]\frac{3.1+5}{3}[/tex]
f(x) = [tex]\frac{9.1+15}{3}[/tex]
f(x) = [tex]\frac{9+15}{3}[/tex]
f(x) = [tex]\frac{24}{3}[/tex]
f(x) = 8
D) f ( 1/5 ) =
f(x) = 3 . [tex]\frac{1}{5}[/tex] + 5
f(x) = [tex]\frac{3}{1}[/tex] . [tex]\frac{1}{5}[/tex] + [tex]\frac{5}{1}[/tex]
f(x) = [tex]\frac{3.1+5}{5}[/tex]
f(x) = [tex]\frac{15.1+25}{5}[/tex]
f(x) = [tex]\frac{15+25}{5}[/tex]
f(x) = [tex]\frac{40}{5}[/tex]
E) f ( 5 ) =
f(x) = 3 . 5 + 5
f(x) = 15 + 5
f(x) = 20
F) f ( 3 ) =
f(x) = 3 . 3 + 5
f(x) = 9 + 5
f(x) = 14
G) f ( 2 ) =
f(x) = 3 . 2 + 5
f(x) = 6 + 5
f(x) = 11
H) f ( 1 ) =
f(x) = 3 . 1 + 5
f(x) = 3 + 5
I) f ( 1/2 ) =
f(x) = 3 . [tex]\frac{1}{2}[/tex] + 5
f(x) = [tex]\frac{3}{1}[/tex] . [tex]\frac{1}{2}[/tex] + [tex]\frac{5}{1}[/tex]
f(x) = [tex]\frac{3.1+5}{2}[/tex]
f(x) = [tex]\frac{6.1+10}{2}[/tex]
f(x) = [tex]\frac{6+10}{2}[/tex]
f(x) = [tex]\frac{16}{2}[/tex]
J) f ( 1/7 ) =
f(x) = 3 . [tex]\frac{1}{7}[/tex] + 5
f(x) = [tex]\frac{3}{1}[/tex] . [tex]\frac{1}{7}[/tex] + [tex]\frac{5}{1}[/tex]
f(x) = [tex]\frac{3.1+5}{7}[/tex]
f(x) = [tex]\frac{21.1+35}{7}[/tex]
f(x) = [tex]\frac{21+35}{7}[/tex]
f(x) = [tex]\frac{56}{7}[/tex]
K) f ( 1/9 ) =
f(x) = 3 . [tex]\frac{1}{9}[/tex] + 5
f(x) = [tex]\frac{3}{1}[/tex] . [tex]\frac{1}{9}[/tex] + [tex]\frac{5}{1}[/tex]
f(x) = [tex]\frac{3.1+5}{9}[/tex]
f(x) = [tex]\frac{27.1+45}{9}[/tex]
f(x) = [tex]\frac{27+45}{9}[/tex]
f(x) = [tex]\frac{72}{9}[/tex]
L) f ( 1/4 ) =
f(x) = 3 . [tex]\frac{1}{4}[/tex] + 5
f(x) = [tex]\frac{3}{1}[/tex] . [tex]\frac{1}{4}[/tex] + [tex]\frac{5}{1}[/tex]
f(x) = [tex]\frac{3.1+5}{4}[/tex]
f(x) = [tex]\frac{12.1+20}{4}[/tex]
f(x) = [tex]\frac{12+20}{4}[/tex]
f(x) = [tex]\frac{32}{4}[/tex]
Explicação passo a passo:
Espero ter te ajudadooo, marca como melhor resposta :)
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Lista de comentários
Resposta:
A) f (-1) =
f(x) = 3 . (-1) + 5
f(x) = - 3 + 5
f(x) = 2
B) f (-3) =
f(x) = 3 . (-3) + 5
f(x) = - 9 + 5
f(x) = - 4
C) f ( 1/3 ) =
f(x) = 3 . [tex]\frac{1}{3}[/tex] + 5
f(x) = [tex]\frac{3}{1}[/tex] . [tex]\frac{1}{3}[/tex] + [tex]\frac{5}{1}[/tex]
f(x) = [tex]\frac{3.1+5}{3}[/tex]
f(x) = [tex]\frac{3.1+5}{3}[/tex]
f(x) = [tex]\frac{9.1+15}{3}[/tex]
f(x) = [tex]\frac{9+15}{3}[/tex]
f(x) = [tex]\frac{24}{3}[/tex]
f(x) = 8
D) f ( 1/5 ) =
f(x) = 3 . [tex]\frac{1}{5}[/tex] + 5
f(x) = [tex]\frac{3}{1}[/tex] . [tex]\frac{1}{5}[/tex] + [tex]\frac{5}{1}[/tex]
f(x) = [tex]\frac{3.1+5}{5}[/tex]
f(x) = [tex]\frac{15.1+25}{5}[/tex]
f(x) = [tex]\frac{15+25}{5}[/tex]
f(x) = [tex]\frac{40}{5}[/tex]
f(x) = 8
E) f ( 5 ) =
f(x) = 3 . 5 + 5
f(x) = 15 + 5
f(x) = 20
F) f ( 3 ) =
f(x) = 3 . 3 + 5
f(x) = 9 + 5
f(x) = 14
G) f ( 2 ) =
f(x) = 3 . 2 + 5
f(x) = 6 + 5
f(x) = 11
H) f ( 1 ) =
f(x) = 3 . 1 + 5
f(x) = 3 + 5
f(x) = 8
I) f ( 1/2 ) =
f(x) = 3 . [tex]\frac{1}{2}[/tex] + 5
f(x) = [tex]\frac{3}{1}[/tex] . [tex]\frac{1}{2}[/tex] + [tex]\frac{5}{1}[/tex]
f(x) = [tex]\frac{3.1+5}{2}[/tex]
f(x) = [tex]\frac{6.1+10}{2}[/tex]
f(x) = [tex]\frac{6+10}{2}[/tex]
f(x) = [tex]\frac{16}{2}[/tex]
f(x) = 8
J) f ( 1/7 ) =
f(x) = 3 . [tex]\frac{1}{7}[/tex] + 5
f(x) = [tex]\frac{3}{1}[/tex] . [tex]\frac{1}{7}[/tex] + [tex]\frac{5}{1}[/tex]
f(x) = [tex]\frac{3.1+5}{7}[/tex]
f(x) = [tex]\frac{21.1+35}{7}[/tex]
f(x) = [tex]\frac{21+35}{7}[/tex]
f(x) = [tex]\frac{56}{7}[/tex]
f(x) = 8
K) f ( 1/9 ) =
f(x) = 3 . [tex]\frac{1}{9}[/tex] + 5
f(x) = [tex]\frac{3}{1}[/tex] . [tex]\frac{1}{9}[/tex] + [tex]\frac{5}{1}[/tex]
f(x) = [tex]\frac{3.1+5}{9}[/tex]
f(x) = [tex]\frac{27.1+45}{9}[/tex]
f(x) = [tex]\frac{27+45}{9}[/tex]
f(x) = [tex]\frac{72}{9}[/tex]
f(x) = 8
L) f ( 1/4 ) =
f(x) = 3 . [tex]\frac{1}{4}[/tex] + 5
f(x) = [tex]\frac{3}{1}[/tex] . [tex]\frac{1}{4}[/tex] + [tex]\frac{5}{1}[/tex]
f(x) = [tex]\frac{3.1+5}{4}[/tex]
f(x) = [tex]\frac{12.1+20}{4}[/tex]
f(x) = [tex]\frac{12+20}{4}[/tex]
f(x) = [tex]\frac{32}{4}[/tex]
f(x) = 8
Explicação passo a passo:
Espero ter te ajudadooo, marca como melhor resposta :)