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Surimi2
@Surimi2
May 2019
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Bonsoir j'ai cet exercice à faire et je ne comprends pas la trigonométrie
pouvez-vous m'aider svp?
trouvez les nombres x de l'intervalles [0; 2/pi] tels que:
cos x=cos pi/3 ; sin x=sin pi/6 ; cos x=cos 3pi/4
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Geijutsu
Verified answer
Bonsoir,
cos(x) = cos(
π/3) ⇔ x = π/3 ou x = 5π/3
sin(x) = sin(π/6) ⇔ x = π/6 ou x = 5π/6
cos(x) = cos(3π/4) ⇔ x = 3π/4 ou x = 5π/4
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surimi2
January 2021 | 0 Respostas
Bonjour, comment je peux trouver le sens de variation de f(x)= 2x-4/-3x+6 ? merci :)
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surimi2
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Bonsoir je dois faire les exercies 23, 25 et 27 mais je bloque dans mes calculs, quelqu'un peut m'aider svp? Merci beaucoup
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Surimi2
May 2019 | 0 Respostas
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Lista de comentários
Verified answer
Bonsoir,cos(x) = cos(π/3) ⇔ x = π/3 ou x = 5π/3
sin(x) = sin(π/6) ⇔ x = π/6 ou x = 5π/6
cos(x) = cos(3π/4) ⇔ x = 3π/4 ou x = 5π/4