Besoin d'aide ; P=(4a-5)(2a-3)+(5a+7)(4a-5) a) Développer b) Factoriser c) a= 0 a= -2 a= 5/4
a) P = (4a-5)(2a-3)+(5a+7)(4a-5)
P = 8a²-12a-10a+15+(20a²-25a+28a-35)
= 8a²-12a-10a+15+20a²-25a+28a-35
P = 28a²-19a-20
b) P = (4a-5)(2a-3)+(5a+7)(4a-5)
= (4a-5)[(2a-3)+(5a+7)}
=(4a-5)(2a-3+5a+7)
P = (4a-5)(7a+4)
c) a=0
P = (4*0-5)(7*0+4)= -5*4 = -20
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a) P = (4a-5)(2a-3)+(5a+7)(4a-5)
P = 8a²-12a-10a+15+(20a²-25a+28a-35)
= 8a²-12a-10a+15+20a²-25a+28a-35
P = 28a²-19a-20
b) P = (4a-5)(2a-3)+(5a+7)(4a-5)
= (4a-5)[(2a-3)+(5a+7)}
=(4a-5)(2a-3+5a+7)
P = (4a-5)(7a+4)
c) a=0
P = (4*0-5)(7*0+4)= -5*4 = -20