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pierrefontaine
@pierrefontaine
June 2021
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je voudrais la derivé de cette fonction : 8x-3x²/5 Merci de votre aide
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charlesetlou
Soit u et v deux fonctions alors (u/v)'=(u'v-v'u)/vcarré
Ici : u=8x-3xcarré u'=-6x+8
v=5 donc v'=0
u'v-v'u=5(-6x+8)-0
=-30x+40
(u'v-v'u)/vcarré
=(-30x+40)/25
=(-6x+8)/5
= la dérivée que tu cherchais
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pierrefontaine
Enfaite la fonction ces 8x-(3x^2/5)
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Ici : u=8x-3xcarré u'=-6x+8
v=5 donc v'=0
u'v-v'u=5(-6x+8)-0
=-30x+40
(u'v-v'u)/vcarré
=(-30x+40)/25
=(-6x+8)/5
= la dérivée que tu cherchais