Resposta:

[tex]\Large{\begin{array}{i}\sf 5(x-3)-4(x+2)=2+3(1-2x)\\ \\ \sf 5x-15-4x-8=2+3-6x\\ \\ \sf x-23=5-6x\\ \\\sf x+6x=5+23\\ \\ \sf 7x=28\\ \\ \sf x=\dfrac{28}{7}\\ \\ \\ \sf x=4\end{array}[/tex]