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Angelicea
@Angelicea
April 2019
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Quelqu'un pourrait m'aider à résoudre cette équation svp. ?
Je galère... :/
(6 x – 2)²- (x+4)² =0
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Commentaires (1)
(6 x – 2)²- (x+4)² =0
((6 x – 2)- (x+4)][
(6 x – 2)+ (x+4)] =0
(6x-2-x-4)(6x-2+x+4) = 0
(5x-6)(7x+2) = 0
5x-6 = 0
5x = 6
x = 6/5
7x+2 = 0
7x = -2
x =-2/7
2 votes
Thanks 1
angelicea
Merci beaucoup! :D
geekkhalil
Salut :) :)
(6 x – 2)²- (x+4)² =0
Alors
(6 x – 2)
(6 x – 2) -
(x+4)
(x+4) =0
(5x-6) (7x+2) = 0
35x²-32x-12 = 0
Soulution
x = -
1 votes
Thanks 1
angelicea
Merci aussi mais il y a un problème à la fin ^^
angelicea
oui .
angelicea
merci quand même :)
geekkhalil
hhhhhhh mais la meme soulution hhhhhh
angelicea
Oui c vrai mais pas la deuxième: 6/5
geekkhalil
je ris
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((6 x – 2)- (x+4)][(6 x – 2)+ (x+4)] =0
(6x-2-x-4)(6x-2+x+4) = 0
(5x-6)(7x+2) = 0
5x-6 = 0
5x = 6
x = 6/5
7x+2 = 0
7x = -2
x =-2/7
(6 x – 2)²- (x+4)² =0
Alors
(6 x – 2)(6 x – 2) - (x+4)(x+4) =0
(5x-6) (7x+2) = 0
35x²-32x-12 = 0
Soulution
x = -