Articles
Register
Sign In
Search
MamABiiB
@MamABiiB
April 2019
2
91
Report
(
7x+1)2-(3x+4)2=0 svp!!!!
(6x-1)2-(2x+1)2=0
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
winner123
Verified answer
Bonjour
7x+1)2-(3x+4)2=0
14x +2 - 6x + 8 = 0
8x +10 = 0
8x = -10
x = -10/8
x = - 5/4
(6x-1)2-(2x+1)2=0
12x -2 -4x - 2 = 0
8x - 4 = 0
8x = 4
x = 4/8
x = 1/2
0 votes
Thanks 1
Rafaelraphael
c'est pas fois 2 mais au carée
geekkhalil
Salut :)
(7x+1)2-(3x+4)2=0
2 (4 x-3) = 0
8 x-6 = 0
(6x-1)2-(2x+1)2=0
4 (2 x-1) = 0
8 x-4 = 0
1 votes
Thanks 1
Rafaelraphael
c'est pas fois 2 mais au carée
winner123
alors le symbole du carré se trouve sous la touche ECHAP. Désolée mais je l'ai pris pour x 2
geekkhalil
oui il ya le symbole du carré se trouve sous la touche ECHAP et aussi il ya une icon de symble lorsque tu veux poser le devoir
More Questions From This User
See All
MamABiiB
June 2021 | 0 Respostas
Responda
MamABiiB
April 2019 | 0 Respostas
Vecteurs rapidement svp !! juste les 1,2,3 svp
Responda
MamABiiB
April 2019 | 0 Respostas
Svp c est sur les statistiques. et proportions
Responda
MamABiiB
April 2019 | 0 Respostas
SVP exercice de volume
Responda
MamABiiB
April 2019 | 0 Respostas
Responda
MamABiiB
April 2019 | 0 Respostas
Juste pour le b du 3) svp
Responda
MamABiiB
April 2019 | 0 Respostas
Responda
×
Report "( 7x+1)2-(3x+4)2=0 svp!!!! (6x-1)2-(2x+1)2=0.... Pergunta de ideia de MamABiiB"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonjour7x+1)2-(3x+4)2=0
14x +2 - 6x + 8 = 0
8x +10 = 0
8x = -10
x = -10/8
x = - 5/4
(6x-1)2-(2x+1)2=0
12x -2 -4x - 2 = 0
8x - 4 = 0
8x = 4
x = 4/8
x = 1/2
(7x+1)2-(3x+4)2=0
2 (4 x-3) = 0
8 x-6 = 0
(6x-1)2-(2x+1)2=0
4 (2 x-1) = 0
8 x-4 = 0