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Calculer en respectant les priorités opératoires..
1) A = (1/5 - 3/4) x 16/7
2) B = ( 1/4 - 7/12) : (7/6+7/16)
3) C = ( 3/4 + 7/12 ) x ( 6/5 : 4/15 )
4) D = 1/4 - 3/4 x 16/9
Calculer en respectant les priorités opératoires..
1) A = (1/5 - 3/4) x 16/7
2) B = ( 1/4 - 7/12) : (7/6+7/16)
3) C = ( 3/4 + 7/12 ) x ( 6/5 : 4/15 )
4) D = 1/4 - 3/4 x 16/9
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Bonjour,1) A = (1/5 - 3/4) x 16/7
A = (1 x 4 / 5 x 4 - 3 x 5 / 4 x 5) x 16/7
A = (4/20 - 15/20) x 16/7
A = - 11/20 x 16/7
A = - 176/140
A = 4 x - 44 / 4 x 35
A = - 44/35
2) B = ( 1/4 - 7/12) : (7/6+7/16)
B = (1 x 3 / 4 x 3 - 7/12) : (7 x 8/ 6 x 8 + 7 x 3 / 16 x 3)
B = (3/12 - 7/12) : (56/48 + 21/48)
B = - 4/12 : 77/48
B = - 4/12 x 48/77
B = - 192/924
B = 12 x - 16 / 12 x 77
B = - 16/77
3) C = ( 3/4 + 7/12 ) x ( 6/5 : 4/15 )
C = (3 x 3 / 4 x 3 + 7/12) x (6/5 x 15/4)
C = (9/12 + 7/12) x 90/20
C = 16/12 x 90/20
C = 1440/240
C = 240 x 6 / 240 x 1
C = 6
4) D = 1/4 - 3/4 x 16/9
D = 1/4 - 48/36
D = 1 x 9 / 4 x 9 - 48/36
D = 9/36 - 48/36
D = - 39/36
D = 3 x - 13 / 3 x 12
D = - 13/12