Resposta:
[tex]a)2+3\div \:8-5\times \:3=-\frac{101}{8}\\b)-9+31\div \:6\times \:4+12=\frac{71}{3}\\c)5\times \:7\div \:2+47-5=\frac{119}{2}\\d)6\times \:3+10-1+37=64\\e)-4+3+7\times \:15\div \:2=\frac{103}{2}[/tex]
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Resposta:
[tex]a)2+3\div \:8-5\times \:3=-\frac{101}{8}\\b)-9+31\div \:6\times \:4+12=\frac{71}{3}\\c)5\times \:7\div \:2+47-5=\frac{119}{2}\\d)6\times \:3+10-1+37=64\\e)-4+3+7\times \:15\div \:2=\frac{103}{2}[/tex]