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aierdna
@aierdna
August 2022
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A derivada da funçãof(x)=(2x>2-3)>2 é;
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fagnerdi
Oi :)
F(x) = (2x²-3)²
f'(x)= 2(2x²-3)²⁻¹.(2x²-3)'
f'(x)= 2(2x²-3)¹ (4x-0)
f'(x)=8x(2x²-3)
f'(x)=16x³-24x
Outra forma de resolver mais rápido seria desenvolver antes de derivar:
f(x)= (2x²-3)²
f(x)=4x⁴-12x²+9
f'(x)=4.4x⁴⁻¹ - 12.2x²⁻¹ +0
f'(x) 16x³ - 24x
Agora fica com vc a melhor forma ;)
Qualquer dúvida comenta aí.
0 votes
Thanks 1
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F(x) = (2x²-3)²
f'(x)= 2(2x²-3)²⁻¹.(2x²-3)'
f'(x)= 2(2x²-3)¹ (4x-0)
f'(x)=8x(2x²-3)
f'(x)=16x³-24x
Outra forma de resolver mais rápido seria desenvolver antes de derivar:
f(x)= (2x²-3)²
f(x)=4x⁴-12x²+9
f'(x)=4.4x⁴⁻¹ - 12.2x²⁻¹ +0
f'(x) 16x³ - 24x
Agora fica com vc a melhor forma ;)
Qualquer dúvida comenta aí.