a) On pose E= (y - 4)² - y (y - 10) 1) Développer et réduire E 2) Résoudre l'équation E= 16 b) On po.... Pergunta de ideia deCharlotte75

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April 2019 2 56 Report

a) On pose E= (y - 4)² - y (y - 10) 1) Développer et réduire E 2) Résoudre l'équation E= 16 b) On pose F= (7y - 3)² - 5² 1) Factoriser F 2) Résoudre l'équation F= 0

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munbly

Verified answer

y+16-2*y*16-y²-10y

y-42y-y²+16

41y-y²+16

E=16

41y-y²+16=0

41y-y²=-16

y-y²=-16/41

0 votes Thanks 0

xxx102

Bonjour,

1) $E = \left(y-4\right)^2-y\left(y-10\right)\\ E = y^2-8y+16-\left(y^2-10y\right)\\ E = y^2-8y+16-y^2+10y\\ E = 2y+16$

2) $2y+16 = 16\\ 2y = 0\\y=0$

b) $F = \left(7y-3\right)^2-5^2\\ F = \left(7y-3+5\right)\left(7y-3-5\right)\\ F = \left(7y+2\right)\left(7y-8\right)$

Si un produit est nul, alors l'un au moins de ses facteurs est nul, donc :

$7y+2 = 0\\ 7y = -2 \\y = -\frac 27$

$7y-8 = 0 \\7y = 8 \\y =\frac 87$

0 votes Thanks 1

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