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Oliviapassionch
@Oliviapassionch
April 2019
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À rendre pour demain !!!! Je n'y arrive pas
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ProblemeEnMath
SALUT !!
Tout d'abord il faut convertir => 1 A = 1000 mA (pour sa c'est bon ?)
Ensuite :
1) 40mA= 40.10(-3)x6.24x10(18)
nombre électrons libres(1seconde)= 40.10(-3)*6.24*10(18)
= 40*6.24*10(-3+18)
= 249.6*10(15)
= 2.496*10(17)
2) 20min=20*60s=1600s
nombre électrons libres(20min)= 2.496*10(17)*1600
= 2.496*10(17)*1.6*10(3)
= 2.496*1.6*10(17+3)
= 3.9936*10(
20)
(entre les parenthèse c'est les Puissances)
2 votes
Thanks 1
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Lista de comentários
Tout d'abord il faut convertir => 1 A = 1000 mA (pour sa c'est bon ?)
Ensuite :
1) 40mA= 40.10(-3)x6.24x10(18)
nombre électrons libres(1seconde)= 40.10(-3)*6.24*10(18)
= 40*6.24*10(-3+18)
= 249.6*10(15)
= 2.496*10(17)
2) 20min=20*60s=1600s
nombre électrons libres(20min)= 2.496*10(17)*1600
= 2.496*10(17)*1.6*10(3)
= 2.496*1.6*10(17+3)
= 3.9936*10(20)
(entre les parenthèse c'est les Puissances)