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nathalia4108
@nathalia4108
March 2022
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A reta que passa pelos pontos(4,1) e (1,-1) tem equação: ?
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GFerraz
(4,1): quando x = 4, y = 1
y = ax + b
1 = 4a + b
b = 1 - 4a
(1,-1): Quando x = 1, y = -1
y = ax + b
-1 = a + b
Substituímos o valor encontrado de 'b'
-1 = a + (1 - 4a)
-1 = a + 1 - 4a
-2 = -3a
a = 2/3
b = 1 - 4a
b = 1 - 8/3
b = 3/3 - 8/3
b = -5/3
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y = ax + b
1 = 4a + b
b = 1 - 4a
(1,-1): Quando x = 1, y = -1
y = ax + b
-1 = a + b
Substituímos o valor encontrado de 'b'
-1 = a + (1 - 4a)
-1 = a + 1 - 4a
-2 = -3a
a = 2/3
b = 1 - 4a
b = 1 - 8/3
b = 3/3 - 8/3
b = -5/3