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heloisiiasmin02
@heloisiiasmin02
March 2022
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a solução da inequação (x-3) . (x²+3x+10)<0 é
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Mario123098m
-x²+3x+10
∆= 9+40=49
x=(-3+-7)/(-2)
x=4/-2=-2
x=-10/-2=5
3 votes
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heloisiiasmin02
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-x²+3x+10
∆= 9+40=49
x=(-3+-7)/(-2)
x=4/-2=-2
x=-10/-2=5