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karladaniielly
@karladaniielly
October 2021
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a soma das medidas dos angulos internos de um poligono regular de n lados è 2340.determine n?
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msffernanda
Sn = (n-2).180
180n - 360 = 2340
180n = 2340 + 360
18n = 234 + 36
18n = 270
n = 270/18
n = 90/6
n = 15
53 votes
Thanks 134
mozarth11
Verified answer
S=(n-2).180
2340 = n-2 .180
2340 = 180n - 360
2340 + 360 = 180n
2700 = 180n
N=15
51 votes
Thanks 93
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Lista de comentários
180n - 360 = 2340
180n = 2340 + 360
18n = 234 + 36
18n = 270
n = 270/18
n = 90/6
n = 15
Verified answer
S=(n-2).1802340 = n-2 .180
2340 = 180n - 360
2340 + 360 = 180n
2700 = 180n
N=15