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Safaa59860
@Safaa59860
April 2019
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A=(2x+3)(3x-5)+(2x+3)(x-7)
1-developper et réduire a
2-factoriser a
3-calculer a pour x=2
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nonotata
A=(2x+3)(3x-5)+(2x+3)(x-7)
a = 6x²-10x+9x-15+2x²-14x+3x-21
a = 8x² -12x -36
factoriser
A=(2x+3)(3x-5)+(2x+3)(x-7)
a =(2x-3)(3x-5+x-7)
a =(2x-3)(4x-12)
a = 4(2x-3)(x-3)
calculer a pour x = 2
on sait que a = 8x²12x-36
a =8(2)² -12(2) -36
a =32 -24-36
a = -28
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a = 6x²-10x+9x-15+2x²-14x+3x-21
a = 8x² -12x -36
factoriser
A=(2x+3)(3x-5)+(2x+3)(x-7)
a =(2x-3)(3x-5+x-7)
a =(2x-3)(4x-12)
a = 4(2x-3)(x-3)
calculer a pour x = 2
on sait que a = 8x²12x-36
a =8(2)² -12(2) -36
a =32 -24-36
a = -28