Articles
Register
Sign In
Search
Thomaspeguy
@Thomaspeguy
May 2019
1
118
Report
ABC est un trapèze rectangle de bases AB et CD tel que AB = AD = 4,5 et DC = 6 . a) calcule la mesure de l'angle ACD arrondie au degré b) calcule la longueur de la diagonale AC c) calcule la longueur BD arrondie au millimétre merci de votreréponse
Please enter comments
Please enter your name.
Please enter the correct email address.
Agree to
terms and service
You must agree before submitting.
Send
Lista de comentários
chrystine
Verified answer
Bonsoir,
a) tan ACD=AD/DC
tanACD=4.5/6≈37°
b)ACD est rectangle en D,d'après la propriété de pythagore
AC²=AD²+DC²
AC²=4.5²+6²
AC²=20.25+36
AC²=56.25
AC=√56.25
AC=7.5 cm
c)ABD est rectangle en A. D'après la propriété le pythagore,
BD²=AB²+AD²
BD²=4.5²+4.5²
BD²=20.25+20.25
BD²=40.5
BD=√40.5
BD=6.4 cm
2 votes
Thanks 4
More Questions From This User
See All
thomaspeguy
May 2021 | 0 Respostas
Responda
thomaspeguy
May 2021 | 0 Respostas
Responda
thomaspeguy
January 2021 | 0 Respostas
Responda
thomaspeguy
January 2021 | 0 Respostas
Responda
thomaspeguy
January 2021 | 0 Respostas
Responda
thomaspeguy
December 2020 | 0 Respostas
Responda
thomaspeguy
December 2020 | 0 Respostas
Responda
thomaspeguy
October 2020 | 0 Respostas
Responda
thomaspeguy
October 2020 | 0 Respostas
Responda
Thomaspeguy
May 2019 | 0 Respostas
Responda
×
Report "ABC est un trapèze rectangle de bases AB et CD tel que AB = AD = 4,5 et DC = 6 . a) calcule la mesur.... Pergunta de ideia de Thomaspeguy"
Your name
Email
Reason
-Select Reason-
Pornographic
Defamatory
Illegal/Unlawful
Spam
Other Terms Of Service Violation
File a copyright complaint
Description
Helpful Links
Sobre nós
Política de Privacidade
Termos e Condições
direito autoral
Contate-Nos
Helpful Social
Get monthly updates
Submit
Copyright © 2024 ELIBRARY.TIPS - All rights reserved.
Lista de comentários
Verified answer
Bonsoir,a) tan ACD=AD/DC
tanACD=4.5/6≈37°
b)ACD est rectangle en D,d'après la propriété de pythagore
AC²=AD²+DC²
AC²=4.5²+6²
AC²=20.25+36
AC²=56.25
AC=√56.25
AC=7.5 cm
c)ABD est rectangle en A. D'après la propriété le pythagore,
BD²=AB²+AD²
BD²=4.5²+4.5²
BD²=20.25+20.25
BD²=40.5
BD=√40.5
BD=6.4 cm