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Thomaspeguy
@Thomaspeguy
May 2019
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ABC est un trapèze rectangle de bases AB et CD tel que AB = AD = 4,5 et DC = 6 . a) calcule la mesure de l'angle ACD arrondie au degré b) calcule la longueur de la diagonale AC c) calcule la longueur BD arrondie au millimétre merci de votreréponse
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chrystine
Verified answer
Bonsoir,
a) tan ACD=AD/DC
tanACD=4.5/6≈37°
b)ACD est rectangle en D,d'après la propriété de pythagore
AC²=AD²+DC²
AC²=4.5²+6²
AC²=20.25+36
AC²=56.25
AC=√56.25
AC=7.5 cm
c)ABD est rectangle en A. D'après la propriété le pythagore,
BD²=AB²+AD²
BD²=4.5²+4.5²
BD²=20.25+20.25
BD²=40.5
BD=√40.5
BD=6.4 cm
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Lista de comentários
Verified answer
Bonsoir,a) tan ACD=AD/DC
tanACD=4.5/6≈37°
b)ACD est rectangle en D,d'après la propriété de pythagore
AC²=AD²+DC²
AC²=4.5²+6²
AC²=20.25+36
AC²=56.25
AC=√56.25
AC=7.5 cm
c)ABD est rectangle en A. D'après la propriété le pythagore,
BD²=AB²+AD²
BD²=4.5²+4.5²
BD²=20.25+20.25
BD²=40.5
BD=√40.5
BD=6.4 cm