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Elise31
@Elise31
April 2019
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Aider moi svp l'exercice n.53, je n'y arrive pas !!
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antoine69
(3x-5)² - (3x-5)(x+4)= 9x²-30x+25-3x²+12-5x-20=6x² -23x +5
(3x-5)(3x-5+x+4) = (3x-5)(4x-1)
pour x =1
(3x1-5)x(4x1-1) = -1x3=-3
pour x=4.5
(3x4.5-5)(4x4.5-1)= 8.5 x17=144.5
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IceQueen
a) F = (3x-5)^2 - (3x-5)(x+4)
= (3x-5)(3x-5) - (3x-5)(x+4)
= 9x^2 -15x -15x+25 - (3x^2+12x -5x -20)
= 9x^2 -30x + 25 - ( 3x^2+ 7x - 20)
= 9x^2 - 30x + 25 -3x^2 -7x +20
= 6x^2 -37x +45
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Elise31
April 2019 | 0 Respostas
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Elise31
April 2019 | 0 Respostas
Je n'est rien compris a cet exercice ! Si quelqu'un pouvais m'aider. Merci
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(3x-5)(3x-5+x+4) = (3x-5)(4x-1)
pour x =1
(3x1-5)x(4x1-1) = -1x3=-3
pour x=4.5
(3x4.5-5)(4x4.5-1)= 8.5 x17=144.5
= (3x-5)(3x-5) - (3x-5)(x+4)
= 9x^2 -15x -15x+25 - (3x^2+12x -5x -20)
= 9x^2 -30x + 25 - ( 3x^2+ 7x - 20)
= 9x^2 - 30x + 25 -3x^2 -7x +20
= 6x^2 -37x +45