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Clemenciia
@Clemenciia
June 2021
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Aider moi svp.. (URGENT)
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Omnes
Salut,
Dans HAC triangle rectangle en H, AC = 17cm et HC = 8cm
Selon le théorème de Pythagore :
AC² = HC² + AH²
HA² = AC² - HC²
HA² = 17² - 8²
HA² = 225
HA = 15
On a donc HA = 15cm.
Dans ABH triangle rectangle en H, HA = 15cm, AB = 25cm
Selon le théorème de pythagore :
AB² = AH² + BH²
BH² = AB²-AH²
BH² = 25² - 15²
BH² = 400
BH = 20
Ainsi, AH = 15cm et BH = 20cm
De plus, BC = BH+HC = 20 + 8 = 28cm
Aabc = BC * AH / 2
Aabc = 28 * 15 / 2 = 420/2 = 210
Ainsi l'aire du triangle ABC est de 210cm².
Bonne journée !
0 votes
Thanks 1
Clemenciia
Merci beaucoup, bonne journée ^^
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Dans HAC triangle rectangle en H, AC = 17cm et HC = 8cm
Selon le théorème de Pythagore :
AC² = HC² + AH²
HA² = AC² - HC²
HA² = 17² - 8²
HA² = 225
HA = 15
On a donc HA = 15cm.
Dans ABH triangle rectangle en H, HA = 15cm, AB = 25cm
Selon le théorème de pythagore :
AB² = AH² + BH²
BH² = AB²-AH²
BH² = 25² - 15²
BH² = 400
BH = 20
Ainsi, AH = 15cm et BH = 20cm
De plus, BC = BH+HC = 20 + 8 = 28cm
Aabc = BC * AH / 2
Aabc = 28 * 15 / 2 = 420/2 = 210
Ainsi l'aire du triangle ABC est de 210cm².
Bonne journée !