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jeanne6969
@jeanne6969
January 2021
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Aidez moi pour cette exercice svp
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AhYan
BCD = triangle rectangle en C.
Donc on a:
Tan(BDC) = BC/CD = 18/87 ≈0,207
angle BDC = 11,7°
Angle ADC = angle ADB + angle BDC = 38+11,7 = 49,7°
Tan(ADC) = AC/CD
AC = Tan(ADC)×CD
AC = Tan(49,7)×87 ≈ 102,59m
AB = AC-BC = 102,59-18 = 84,59m
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Est ce que quelqu'un peut m'aider pour cette exercice svp. Merci
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Est ce que vous pouvez m'aidez svp pour cette exercice merci.
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Je dois faire ces 2 exercices pour demain. Pouvez vous m'aidez svp?
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Lista de comentários
Donc on a:
Tan(BDC) = BC/CD = 18/87 ≈0,207
angle BDC = 11,7°
Angle ADC = angle ADB + angle BDC = 38+11,7 = 49,7°
Tan(ADC) = AC/CD
AC = Tan(ADC)×CD
AC = Tan(49,7)×87 ≈ 102,59m
AB = AC-BC = 102,59-18 = 84,59m