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MxllMarine
@MxllMarine
May 2019
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Aidez moi pour la question 114 s'il vous plaît!
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1)
a) dans C(q), tu remplaces q par 80 et tu calcules
C(q) = 492
b) 80 × 15 = 1 200
oui
2)
a) R(q) = 15q
b) B(q) = R(q) - C(q)
= 15q - (0,08q² - 1,6q + 108)
= -0,08q² + 1,6q + 15q - 108
= 0,08q² + 16,6q - 108
3) Il faut résoudre l'inéquation : B(q) > 400
donc : -0,08q² + 16,6q - 108 > 400
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Lista de comentários
a) dans C(q), tu remplaces q par 80 et tu calcules
C(q) = 492
b) 80 × 15 = 1 200
oui
2)
a) R(q) = 15q
b) B(q) = R(q) - C(q)
= 15q - (0,08q² - 1,6q + 108)
= -0,08q² + 1,6q + 15q - 108
= 0,08q² + 16,6q - 108
3) Il faut résoudre l'inéquation : B(q) > 400
donc : -0,08q² + 16,6q - 108 > 400