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Strubbeclara
@Strubbeclara
April 2019
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AIDEZ MOI SVO
pouvez vous m'aider je suis en 4 ème silvouplai
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winner123
Verified answer
Bonsoir
tu appliques Pythagore
( 5/3)² - ( 4/3)² = 1 ²
25/9 -
16
/9 = 1
9/9 = 1
1 = 1
le triangle est bien rectangle
aire = 4/3 x 1 = 4/3
périmètre = 4/3 + 5/3 + 1= 9/3 + 3/3 = 12/3 = 4
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Verified answer
Bonsoirtu appliques Pythagore
( 5/3)² - ( 4/3)² = 1 ²
25/9 - 16/9 = 1
9/9 = 1
1 = 1
le triangle est bien rectangle
aire = 4/3 x 1 = 4/3
périmètre = 4/3 + 5/3 + 1= 9/3 + 3/3 = 12/3 = 4