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Coldplayfan61
@Coldplayfan61
May 2019
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Aidez moi svp c l ex 8 la c et tt l'ex 9 mrc bcpp
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gsantha
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Bonsoir
Exercice 8
A = (x + 2) (2x - 1) + (x + 2) (3x + 2)
= (x + 2) [(2x - 1) + (3x + 2)]
= (x + 2) (2x - 1 + 3x + 2)
= (x + 2) (5x + 1)
B = (3x + 7) (2x - 9) - (3x + 7) (5x - 7)
= (3x + 7) [(2x - 9) - (5x - 7)]
= (3x + 7) (2x - 9 - 5x + 7)
= (3x + 7) (-3x - 2)
C = (8y + 3) (5y + 7) - 3(8y + 3) (2y - 1)
= (8y + 3) [(5y + 7) - 3(2y - 1)]
= (8y + 3) (5y + 7 - 6y + 1)
= (8y + 3) (-y + 8)
Exercice 9
D = (2x + 3)² + (x - 2) (2x + 3)
= (2x + 3) [(2x + 3) + (x - 2)]
= (2x + 3) (2x + 3 + x - 2)
= (2x + 3) (3x + 1)
E = (2t - 7) - (5y + 1) (2t - 7)
= (2t - 7) [1 - (5y + 1)]
= (2t - 7) (1 - 5y - 1)
= (2t - 7) (-5y + 0)
= -5y (2t - 7)
F = 2y² - y(4y - 7)
= y * 2y - y(4y - 7)
= y [2y - (4y - 7)]
= y (2y - 4y + 7)
= y (-2y + 7)
G = (2t - 5)² + (2t - 5) (x - 1) + 2t - 5
= (2t - 5) [(2t - 5) + (x - 1) + 1]
= (2t - 5) (2t - 5 + x - 1 + 1)
= (2t - 5) (2t + x - 5)
Voilà j'espère avoir pu t'aider ^^
2 votes
Thanks 2
coldplayfan61
merci bcp <3
gsantha
de rien :)
coldplayfan61
<3 <3
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pourriez vous m'aider sur cet exo,g vrmt besoin d'aide c sur les nombres premiers (3e)
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Verified answer
BonsoirExercice 8
A = (x + 2) (2x - 1) + (x + 2) (3x + 2)
= (x + 2) [(2x - 1) + (3x + 2)]
= (x + 2) (2x - 1 + 3x + 2)
= (x + 2) (5x + 1)
B = (3x + 7) (2x - 9) - (3x + 7) (5x - 7)
= (3x + 7) [(2x - 9) - (5x - 7)]
= (3x + 7) (2x - 9 - 5x + 7)
= (3x + 7) (-3x - 2)
C = (8y + 3) (5y + 7) - 3(8y + 3) (2y - 1)
= (8y + 3) [(5y + 7) - 3(2y - 1)]
= (8y + 3) (5y + 7 - 6y + 1)
= (8y + 3) (-y + 8)
Exercice 9
D = (2x + 3)² + (x - 2) (2x + 3)
= (2x + 3) [(2x + 3) + (x - 2)]
= (2x + 3) (2x + 3 + x - 2)
= (2x + 3) (3x + 1)
E = (2t - 7) - (5y + 1) (2t - 7)
= (2t - 7) [1 - (5y + 1)]
= (2t - 7) (1 - 5y - 1)
= (2t - 7) (-5y + 0)
= -5y (2t - 7)
F = 2y² - y(4y - 7)
= y * 2y - y(4y - 7)
= y [2y - (4y - 7)]
= y (2y - 4y + 7)
= y (-2y + 7)
G = (2t - 5)² + (2t - 5) (x - 1) + 2t - 5
= (2t - 5) [(2t - 5) + (x - 1) + 1]
= (2t - 5) (2t - 5 + x - 1 + 1)
= (2t - 5) (2t + x - 5)
Voilà j'espère avoir pu t'aider ^^