Aidez-moi svp c'est très urgent :: La question : les travaux de ce qui suit:: A= 9x²₋ 4 ; B= 64x³₋ 27 ; C= 27x⁴₊64x ; D= (3x₊2)² ₋36 (x₊1)² ; E= (₋2x₊1)²₋(4₋8x) (x₊3)₊(3₋12x²) ; G= 36₋ 16x²
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B= 64x³₋ 27 = (4x-3)(16x² + 12x + 9)
C= 27x⁴₊64x = x(27x^3 + 64) = (x)(3x+4)(9x² +12x+16)
D= (3x₊2)² ₋36 (x₊1)² = [(3x+2)+6(x+1)][(3x+2)-6(x+1)]
=(9x+8)(-3x-4)
E= (₋2x₊1)²₋(4₋8x) (x₊3)₊(3₋12x²) =(2x-1)(2x-1) + 4(2x-1) (x+3) - 3(4x² -1 )
E=(2x-1)(2x-1 +4x+12 - 3(2x+1) ) = (2x-1)(8)
G= 36₋ 16x² =(6-4x)(6+4x)
A=(3x)² -2² =(3x+2)(3x-2).
B=64x³-27
B=(4x)³ - 3³
B=(4x-3)((4x)²+(4x)(3)+3²)=(4x-3)(16x²+12x +9)
C=x(27x³+64)=x((3x)³+4³))=x(3x+4)((3x)²-(3x)(4)+4²)=x(3x+4)(9x²-12x+16)
D=(3x+2)²-36(x+1)²=(3x+2)²-(6(x+1))²=((3x+2)+6(x+1))((3x+2)-6(x+1))
D=(3x+2+6x+6)(3x+2-6x-6)= (9x+8)(-3x-4)
E=(-2x+1)²-(4-8x)(x+3)+(3-12x²) =(1-2x)² - 4(1-2x)(x+3) +3(1-4x²)
E=(1-2x)(1-2x) -(1-2x)(4x+12) +3(1²-(2x)²)
E= (1-2x)(1-2x) -(1-2x)(4x+12) +3(1-2x)(1+2x)
E=(1-2x)((1-2x)-(4x+12)+(3x+6)
E=(1-2x)(1-2x-4x-12 +3+6x)
E=(1-2x)(-8) = -8(1-2x)
G=36-16x²=6² - (4x)² =(6+4x)(6-4x)
bonne chance